Question 1
Calculate the speed of a car that travels 150 metres in 10 seconds. Express it in km/h.
150 ÷ 10 = 15 m/s; 15 × 3.6 = 54 km/h.
Answer
54 km/h
CLASS 7 · SCIENCE · CHAPTER 8
Simple worked answers to all eleven end questions, five exploratory projects, and the chapter’s four activities, pendulum investigation, train-speed task, and motion-data question.
22 worked answers · short steps first, explanations when you need them
Textbook pages 102–104
Question 1
150 ÷ 10 = 15 m/s; 15 × 3.6 = 54 km/h.
54 km/h
Question 2
First: 8 m/s. Second: about 8.89 m/s. Difference: about 0.89 m/s.
The second runner is faster by about 0.89 m/s.
Question 3
360 km = 360,000 m; 360,000 ÷ 25 = 14,400 s = 4 h.
4 hours
Question 4
180 ÷ 3 = 60 km/h; 60 ÷ 3.6 ≈ 16.67 m/s; 60 × 4 = 240 km.
60 km/h; 16.67 m/s; 240 km.
Question 5
18 m/s = 64.8 km/h; 72 − 64.8 = 7.2 km/h.
The train is faster by 7.2 km/h.
Question 6
Steady speed on a straight highway: uniform. Changing speed in traffic: non-uniform.
City traffic is a common example of non-uniform motion.
Question 7
Add 8 m for every 10 s.
At 20 s: 16 m; at 60 s: 48 m.
Question 8
Different distances in equal hours mean non-uniform motion; 180 ÷ 3 = 60 km/h.
Non-uniform; average speed = 60 km/h.
Question 9
Daily motion usually changes speed; examples include buses, walkers, and bicycles in traffic.
Non-uniform motion is more common.
Question 10
Unequal distance increases mean non-uniform speed; 60 ÷ 100 = 0.6 m/s.
Non-uniform; average speed = 0.6 m/s.
Question 11
First parts take 50 + 100 = 150 s; remaining 1,000 m in 50 s needs 20 m/s. Total average: 2,000 ÷ 200 = 10 m/s.
Required speed = 20 m/s; average speed = 10 m/s.
Textbook pages 104
Question Project 1
Try different bowl and hole sizes, time each trial, and repeat the combination closest to 24 minutes.
Record repeated trials; change one feature at a time.
Question Project 2
Measure beats per minute, use the rate to estimate a short time, and write a story about checking the estimate.
At 75 beats per minute, 25 beats are about 20 seconds; pulse timing is approximate.
Question Project 3
Use the same length and release angle, time many swings, repeat, and average.
Consistent setup and repeated measurements reduce timing differences.
Question Project 4
Time 10 swings, divide by 10, then compare average periods for different riders and lengths.
A swing acts like a pendulum. Its length affects the period; rider weight has little effect.
Question Project 5
Speed = distance ÷ time. For example, Paris 2024 men’s 200 m: 200 ÷ 19.46 ≈ 10.28 m/s.
In this sample, Paris 2024 men’s 200 m has the greatest average speed: about 10.28 m/s.
Textbook pages 107–117
Question Activity 8.1
How can you use the marked bottle to measure time after the water has dripped into its lower half?
Mark the water level in the lower half after each minute as the water drips through the small cap hole.
Question Activity 8.2
How do you calculate a pendulum’s time period, and what should repeated readings show?
Count 10 complete oscillations and measure their total time.
Question Think like a scientist: pendulum variables
How can you test whether a pendulum’s length or bob mass affects its time period?
Change one factor at a time.
Question Activity 8.3
What is the smallest time interval shown by the wall clock in the figure?
The smallest interval shown is 1 second.
Question Activity 8.4
How can you compare train speeds between two stations using a railway timetable?
For each train, note the distance between the stations and subtract its departure time from its arrival time.
Question Table 8.3: Comparing trains
Which train moves with uniform linear motion between 10:00 and 11:00, based on the distances in Table 8.3?
Train X moves uniformly because it covers 20 km in each 10-minute interval.